Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm

Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm. Draw line BC = 11 cm. Make an angle of 30° at B and 90° at C using a protractor. Bisect angles B and C, and these bisectors will meet at one-point X. Now draw perpendicular bisectors on BX and CX, which will cut the line segment BC on point Y and Z respectively. Now join XY and XZ to get the required triangle XYZ.
It is given that we have to construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm. We have drawn the triangle using a compass and ruler and justified the construction.

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Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm.

Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ

NCERT Solutions for Class 9 Maths Chapter 11 Constructions Exercise 11.2 Solutions

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construct a triangle xyz in which y=30 z=90 and xy+yz+zx=11 in

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