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6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2
7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2
cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2
cos150
Video solution 1: 6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2
7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2
cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2
cos150
Video solution 2: 6. sin150 Sin(90+60)=+cos60∘=+1/2 sin(180−30)=+sin30∘+1/2
7cos120∘cos(90+30)=−sin30∘=+1/2cos(180∘−60)=−cos60∘=−1/2
cos(90+60)=−sin60∘=−8/2cos(180∘−30)=−cos30=−3/2
cos150
SOLVED: Evaluate each of the following trigonometric expressions sin 60 + cos 45 74)+6):4+44 oy 1 2. 2 sin 30' 2 cos 45 + tan? 60 4 sin 60 + 3 tan
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Unit 2: Use reduction formulae to simplify trig ratios – National Curriculum (Vocational) Mathematics Level 3
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Ex 8.2, 1 (iv) - Evaluate (sin 30° + tan 45° - cosec 60°) / (sec 30° +
Choose the correct option and justify your choice: (i) 2 tan 30°/1 + tan2 30° (A) sin 60° (B) cos 60° (C) tan 60° (D) sin 60° (ii) 1 - tan² 45°/1 + tan² 45° (A) tan 90° (B) 1 (C) sin 45° (D) 0°